2(cos^4x-sin^4x)=1

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Solution for 2(cos^4x-sin^4x)=1 equation:


Simplifying
2(cos4x + -1sin4x) = 1
(cos4x * 2 + -1in4sx * 2) = 1
(2cos4x + -2in4sx) = 1

Solving
2cos4x + -2in4sx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2in4sx' to each side of the equation.
2cos4x + -2in4sx + 2in4sx = 1 + 2in4sx

Combine like terms: -2in4sx + 2in4sx = 0
2cos4x + 0 = 1 + 2in4sx
2cos4x = 1 + 2in4sx

Divide each side by '2os4x'.
c = 0.5o-1s-4x-1 + in4o-1s-3

Simplifying
c = 0.5o-1s-4x-1 + in4o-1s-3

Reorder the terms:
c = in4o-1s-3 + 0.5o-1s-4x-1

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